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  • The points <img alt="\mathrm{A(a, 0), B(0, b), C(c, 0) \& D(0, d)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BA%28a%2C%200%29%2C%20B%280%2C%20b%29%2C%20C%28c%2C%200%29%20

The points \mathrm{A(a, 0), B(0, b), C(c, 0) \& D(0, d)} are such that \mathrm{a c=b d \: \&\: a, b, c, d} are all non-zero. Then the points :

Option: 1

form a parallelogram


Option: 2

do not lie on a circle


Option: 3

form a trapezium


Option: 4

are concyclic


Answers (1)

best_answer

\mathrm{If \: \mathrm{OA} \cdot \mathrm{OC}=\mathrm{OB} \cdot \mathrm{OD}} \left ( \text{Power of point} \right ) then points are concylic

\therefore \quad \mathrm{a} \cdot \mathrm{c}=\mathrm{bd}(\text { true) }

Posted by

vinayak

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