Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The position of the centre of mass of a uniform semi-circular wire of radius $' R\: '$ placed in $x-y$ plane with its centre at the origin and the line joining its ends as $x-axis$ is given by $\left(0, \frac{x R}{\pi}\right)$ .
Then, the value of $|x|$ is__________.

Answers (1)

best_answer

$y_{cm}=\frac{2R}{\pi }$

$x_{cm}=0$

$\therefore x=2$

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Trending Articles/News

anam-khan

DASA, CSAB Special round 2 seat allotment result 2025 declared on csab.nic.in

Latest Question