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  • The potential at a point, due to a positive charge of 100\mu C at a distance of 9m, is

The potential at a point, due to a positive charge of 100\mu C at a distance of 9m, is

Answers (1)

By using

V=9 \times 10^{6} \times \frac{Q}{r}=9 \times 10^{9} \times \frac{100 \times 10^{-6}}{9}=10^{5} V

Posted by

Satyajeet Kumar

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