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The probability, that in a randomly selected 3-digit number at least two digits are odd, is

Option: 1

\frac{19}{36}


Option: 2

\frac{15}{36}


Option: 3

\frac{13}{36}


Option: 4

\frac{23}{36}


Answers (1)

best_answer

Case 1  3 odd digits   \underline{5}\times\underline{5}\times\underline{5}= 125.
Case 2   2  odd- 1 even digit

(i)  if 0 is selected  _  \underline{0}\: \: \underline{0}\: \: 2\times5\times5= 50
(ii) if 0 is not selected  _ _  _  3\times4\times5\times5= 300

Total = 475,
No.of 3 digit numbers = 900

\mathrm{P= \frac{475}{900}= \frac{19}{36}}
Option (A)
 

Posted by

Deependra Verma

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