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  • The probability that there are 53 Sunday in a randomly chosen leap year isOption: 1 <img alt="\frac{1}{7}" src="https://entrancecorner.oncodecogs.com

The probability that there are 53 Sunday in a randomly chosen leap year is

Option: 1

\frac{1}{7}


Option: 2

\frac{1}{14}


Option: 3

\frac{1}{28}


Option: 4

\frac{2}{7}


Answers (1)

best_answer

Leap year \mathrm{=366 \: days =(52 \times 7)+2 \: days}( these two days can be one of the following seven pairs)

so sample space $={ Sun - Mon, Mon-Tue, Tue-Wed, Wed-Thu, Thur-Fri, Fri-Sat, Sat-Sun.}=7 pairs

Fav. cases ={Sun - Mon, Sat - Sun }=2

So Req. probability

=\frac{2}{7}

Posted by

Divya Prakash Singh

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