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  • The radiation corresponding to   transition of hydrogen atom falls on a metal s

The radiation corresponding to 3\rightarrow 2  transition of hydrogen atom falls on a metal surface to produce photoelectrons. These electrons are made to enter a magnetic field of  3 \times10-4  T.  If the radius of the largest circular path followed by these electrons is 10.0 mm, the work function of the metal is close to :

Option: 1

1.8 eV


Option: 2

1.1 eV


Option: 3

0.8 eV


Option: 4

1.6 eV


Answers (1)

best_answer

Radius of charge particle in magnetic field is R=\frac{mv}{qB}

or p=mv= qBR=1.6\times 10^{-19}\times 3\times 10^{-4}\times 10^{-2}

p=4.8\times 10^{-25}

For metal ; energy of rsdius of radiation is

\Delta E_{3\rightarrow 2}=13.6\left ( \frac{1}{4}-\frac{1}{9} \right )=13.6\times \frac{5}{36}

= 1.9 eV.

K.E_{max}=\frac{p^{2}}{2m}=\Delta E-\Phi

\Phi =\Delta E-\frac{p^{2}}{2m}= 1.9eV-\frac{\left ( 4.8\times 10^{-25} \right )^{2}}{2\times 9.1\times 10^{-31}}J

\Phi =1.9eV-1.26\times 10^{-19}J

= 1.9 eV - 0.8 eV

\Phi =1.1 eV

Posted by

Sanket Gandhi

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