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  • The radius of 2nd orbit of  of Bohr's model is <img alt="\mathrm{r_{

The radius of 2nd orbit of \mathrm{He^{+}} of Bohr's model is \mathrm{r_{1}} and that of fourth orbit of \mathrm{Be^{3+}} is represented as \mathrm{r_{2}}. Now the ratio \frac{r_2}{r_1} \text { is } \mathrm{x}: 1. The value of x is _________

Option: 1

2


Option: 2

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Option: 3

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Option: 4

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Answers (1)

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\begin{aligned} & \mathrm{r} \propto \frac{\mathrm{n}^2}{\mathrm{Z}} \\ & \frac{\mathrm{r}_2}{\mathrm{r}_1}=\left(\frac{\mathrm{n}_2}{\mathrm{n}_1}\right)^2 \times \frac{z_1}{\mathrm{z}_2} \\ & \frac{\mathrm{r}_2}{\mathrm{r}_1}=\left(\frac{4}{2}\right)^2 \times \frac{2}{4} \\ & \frac{\mathrm{r}_2}{\mathrm{r}_1}=2 \\ & \mathrm{x}=2 \end{aligned}

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