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  • The radius of fifth orbit of the <img alt="\mathrm{Li}^{++}$is $\times 10^{-12} \mathrm{~m}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BLi%7D%5E%7B&plus;&plus;%7D%24is

The radius of fifth orbit of the \mathrm{Li}^{++}$is $\times 10^{-12} \mathrm{~m}
Take : radius of hydrogen atom =0.5 \overline{1 \AA}

 

Option: 1

425


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

r_n=\frac{0.51 n^2}{z} A^0\\ For \mathrm{Li}^{++}, z=3.\\ \text { So } r_5=0.51 \times \frac{25}{3} \times 10^{-10} \mathrm{~m}=17 \times 25 \times 10^{-12} \mathrm{~m}=425 \times 10^{-12} \mathrm{~m}

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jitender.kumar

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