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The rate constant of a reaction with virus is 1.925 \times 10^{-4} s^{-1}. The time required for the virus to become 75 \% inactivated is.

 

Option: 1

 60 min

 


Option: 2

120 min


Option: 3

180 min


Option: 4

240 min


Answers (1)

best_answer

For a first order reaction

\mathrm{t_{1 / 2}=\frac{0.693}{k}=\frac{0.693}{1.925 \times 10^{-4}}=3600\, s}
                                                              \mathrm{= 60\, min}

\mathrm{t_{75 \%}=2 t_{1 / 2}=2 \times 60=120 \text { min }}.

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Riya

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