Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The ratio of intensities of two waves is 9 : 1. They are producing interference. The ratio of maximum and minimum intensities will beOption: 1 10 : 8

The ratio of intensities of two waves is 9 : 1. They are producing interference. The ratio of maximum and minimum intensities will be

Option: 1

10 : 8                                        

 

                                        

 


Option: 2

 9 : 1


Option: 3

 2 : 1  


Option: 4

  4 : 1


Answers (1)

best_answer
 

The ratio of maximum and minimum intensities

\frac{I_{\max }}{I_{\min }}=\left(\frac{\sqrt{I_{1}}+\sqrt{I_{2}}}{\sqrt{I_{1}}-\sqrt{I_{2}}}\right)^{2}=\left(\frac{\sqrt{I_{1} / I_{2}}+1}{\sqrt{I_{1} / I_{2}}-1}\right)^2=\left(\frac{a_{1}+a_{2}}{a_{1}-a_{2}}\right)^{2}=\left(\frac{a_{1} / a_{2}+1}{a_{1} / a_{2}-1}\right)^{2}

 

  \frac{I_{\max }}{I_{\min }}=\left(\frac{\sqrt{\frac{I_{1}}{I_{2}}}+1}{\sqrt{\frac{I_{1}}{I_{2}}}-1}\right)^{2}=\left(\frac{\sqrt{\frac{9}{1}}+1}{\sqrt{\frac{9}{1}}-1}\right)^2=\frac{4}{1}

Hence, the correct option is (4).

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question