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  • The ratio of the de-Broglie wavelengths of proton and electron having same Kinetic energy: (Assume <img alt="\mathrm{m}_{\mathrm{p}}=\mathrm{m}_{\mathrm{e}} \times 1849" src="https://entrancecorner

The ratio of the de-Broglie wavelengths of proton and electron having same Kinetic energy: (Assume \mathrm{m}_{\mathrm{p}}=\mathrm{m}_{\mathrm{e}} \times 1849)

Option: 1

1:62


Option: 2

1: 30


Option: 3

1: 43


Option: 4

2: 43


Answers (1)

best_answer

\lambda=\frac{\mathrm{h}}{\mathrm{P}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mK}}}
\frac{\lambda_{\mathrm{P}}}{\lambda_{\mathrm{e}}}=\sqrt{\frac{\mathrm{m}_{\mathrm{e}}}{\mathrm{m}_{\mathrm{p}}}}=\sqrt{\frac{\mathrm{m}_{\mathrm{e}}}{1840 \mathrm{me}}}=\frac{1}{\sqrt{1840}}
\frac{\lambda_{\mathrm{P}}}{\lambda_{\mathrm{e}}}=\frac{1}{43} \quad

Posted by

Suraj Bhandari

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