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The reagent, from the following, which converts benzoic acid to benzaldehyde in one step is

Option: 1

\mathrm{LiAlH}_{4}


Option: 2

\mathrm{KMnO}_{4}


Option: 3

\mathrm{MnO}


Option: 4

\mathrm{NaBH}_{4}


Answers (1)

best_answer

\mathrm{MnO} on reaction with \mathrm{PhCOOH} in the presence of formic acid will form \mathrm{Ph\: CHO}

\mathrm{Ph\: COOH+HCOOH\xrightarrow[\Delta ]{MnO}PhCHO+CO_{2}+H_{2}O}

Hence, Option (3) is correct.

Posted by

Pankaj Sanodiya

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