The remainder obtained , when is divided by 15 is
5
0
3
8
each multiple of 15
and
Hence, required remainder = 3
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50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
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