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  • The resistance of a conductivity cell containing 8.01 MKCl  solution at 298K is . If t

The resistance of a conductivity cell containing 8.01 MKCl  solution at 298K is 1834 \Omega. If the conductivity of 0.01 MKCl solution at 298K is 0.135 \times 10^{-3} \mathrm{~scm}^{-1}. Calculate cell constant of the conductivity all.

 

Option: 1

128 \times 10^{-2} \mathrm{~cm}^{-1}


Option: 2

115 \times 10^{-3} \mathrm{~cm}^{-1}


Option: 3

248 \times 10^{-3} \mathrm{~cm}^{-1}


Option: 4

320 \times 10^{-2} \mathrm{~cm}^{-1}


Answers (1)

best_answer

\mathrm{K=\left(\frac{1}{a}\right) \frac{1}{R}}
\mathrm{\frac{1}{a}=K \times R =0.135 \times 10^{-3} \times 1834 }
 \mathrm{=248 \times 10^{-3} \mathrm{~cm}^{-1} }
 

Posted by

himanshu.meshram

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