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The resistivity of a 0.5 M solution of an electrolyte is 7 \times 10^{-3} \Omega \mathrm{cm}. What is its molar conductivity.

Option: 1

1.41 \times 10^4


Option: 2

2.8 \times 10^5


Option: 3

3.26 \times 10^9


Option: 4

2.64 \times 10^6


Answers (1)

best_answer

\rho=7 \times 10^{-3} \Omega \mathrm{cm} \\

\mathrm{C}=0.5 \mathrm{M} \\

\mathrm{ \Lambda_m=\frac{\mathrm{K} \times 1000 }{\mathrm{M}} ~Scm^{2} mol^{-1} }

\mathrm{=\frac{\frac{1}{\rho} \times 1000}{M}=\frac{1 \times 1000}{7 \times 10^{-3} \times 5 \times 10^{-1}} }

                          \mathrm{ =\frac{10^{+7}}{35} \\ }

                          \mathrm{ =2 .8 \times 10^5 }

Posted by

manish painkra

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