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The resistivity of 0.7 \mathrm{M} solution  4 \times 10^{-3} \Omega Its molar conductivity is
 

Option: 1

28 \times 10^3 \mathrm{~cm}^2 \mathrm{~mol}^{-1}


Option: 2

14 \times 10^2 \mathrm{~cm}^2 \mathrm{~mol}^{-1}


Option: 3

35 \times 10^4 \mathrm{~cm}^2 \mathrm{~mol}^{-1}


Option: 4

14 \times 10^3 \mathrm{~cm}^2 \mathrm{~mol}^{-1}


Answers (1)

best_answer

\text { Resistivity }(\rho)=4 \times 10^{-3} \Omega \mathrm{cm}
\mathrm{\text { Molarity }(M)=0.7 \mathrm{M}}
Molar Conductivity:-
\mathrm{\lambda_M=\frac{1}{\rho} \times \frac{1000}{M} }
\mathrm{ \lambda_M=\frac{1}{4 \times 10^{-3}} \times \frac{1000}{0.7} \\ }

\mathrm{\lambda_m=0.35 \times 10^6}
\lambda \mathrm{m}=35 \times 10^4 \mathrm{~cm}^2 \mathrm{~mol}^{-1}.

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Rishi

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