Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The rms current in above fig is

Option: 1

20mA


Option: 2

14.14mA


Option: 3

0


Option: 4

None


Answers (1)

best_answer

As we learnt

 

Peak current / voltage -

 

Maximum value of alternating quantity

V_{0}\rightarrow peak voltage

I_{0}\rightarrow peak current

 

- wherein

At t= \frac{T}{4} for beginning

 

rms value  i_{rms}=\frac{i_0}{\sqrt2}

From given fig peak current i_0=20mA

\Rightarrow i_{rms}=\frac{20}{\sqrt2}

\Rightarrow i_{rms}=14.14mA

Posted by

Nehul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question