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The rods of length \mathrm{4 \mathrm{~cm} \: and \: 6 \mathrm{~cm}} slide along the y-axis and x-axis respectively. If the ends of the rods are concyclic, then locus of the centre of the circle is
 

Option: 1

\mathrm{x}^2=\mathrm{y}^2+5

 


Option: 2

\mathrm{x^2+5=y^2}
 


Option: 3

\mathrm{x^2+y^2=5}
 


Option: 4

None of these.


Answers (1)

best_answer

The ends of the rods are \mathrm{(h-3,0),(h+3,0),(0, k-2),(0, k+2)}, where \mathrm{h, k} is the centre. Hence \mathrm{h^2+4=k^2+9.}

Hence option 1 is correct.

Posted by

manish painkra

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