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  • The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance  an

The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance \mathrm{A} and substance \mathrm{ \mathrm{B}} from the base line are \mathrm{ 3.25 \mathrm{~cm}, 2.08 \mathrm{~cm}} and \mathrm{ 1.05 \mathrm{~cm},} respectively. The ratio of \mathrm{ R_{f}} values of \mathrm{ A } to \mathrm{ B } is _________.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

We know,

\mathrm{R_f=\frac{\text { Distance moved by the substance from base line }}{\text { Distance moved by the solvent from base line }}}

So,

\mathrm{R_f_A=\frac{2.08}{3.25} \text { and } R_{f_B}=\frac{1.05}{3.25}}

Then ratio of \mathrm{R_{f}} values of A to B is

\mathrm{\frac{R_f_A}{R_{f_B}}=\frac{2.08 / 3.25}{1.05 / 3.25}=2}

Answer = 2

Posted by

shivangi.shekhar

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