Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The shortest distance between the circles <img alt="\mathrm{x^2+y^2=1}" src="https://entranc

The shortest distance between the circles \mathrm{x^2+y^2=1} and \mathrm{x^2+y^2-10 x-10 y+41=0} is

Option: 1

\mathrm{\sqrt{41}-1}


Option: 2

\mathrm{ 0}


Option: 3

\mathrm{\sqrt{41}}


Option: 4

\mathrm{5 \sqrt{2}-4}


Answers (1)

best_answer

The distance between the centres of the circles is \mathrm{5 \sqrt{2}}

Sum  of  the  radii = 1 + 3 = 4.

Hence, shortest distance = \mathrm{5 \sqrt{2}-4}

Posted by

seema garhwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow
anam-khan

JEE Main 2026 Registration LIVE: Session 2 exam from April 2 to 9; shift timings, admit card, exam pattern
anam-khan

JEE Main 2026 session 2 registration ends today for BTech, BArch; apply at jeemain.nta.nic.in

Latest Question