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The specific conductance of solution at 25^{\circ} is 0.162 \mathrm{~ohm}^{-1} \mathrm{~cm}^{-1}. The resistance of cell containing solution at same temp was found be 45 \mathrm{~cm}. Calculate the cell constant


 

Option: 1

6.48


Option: 2

7.29


Option: 3

2.67


Option: 4

9.94


Answers (1)

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\begin{aligned} & \mathrm{k=\frac{1}{R}\left(\frac{l}{a}\right) \quad\left(\frac{l}{a}\right)=0.162 \times 45} \\ & \mathrm{0.162=\frac{1}{45}\left(\frac{l}{a}\right) \quad\left(\frac{l}{a}\right)=7.29 }\\ & \end{aligned}

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