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The speed of light in media \mathrm{' A^{\prime} \text { and ' } B \text { ' are } 2.0 \times 10^{10} \mathrm{~cm} / \mathrm{s} \text { and } 1.5 \times 10^{10}}\mathrm{\mathrm{cm} / \mathrm{s}} respectively. A ray of light enters from the medium B to A at an incident angle  \mathrm{' \theta \text { '. }} If the ray suffers total internal reflection, then

Option: 1

\mathrm{\theta=\sin ^{-1}\left(\frac{3}{4}\right)}


Option: 2

\mathrm{\theta>\sin ^{-1}\left(\frac{2}{3}\right)}


Option: 3

\mathrm{\theta<\sin ^{-1}\left(\frac{3}{4}\right)}


Option: 4

\mathrm{\theta>\sin ^{-1}\left(\frac{3}{4}\right)}


Answers (1)

best_answer

\mathrm{n_{A}=\frac{3 \times 10^{8}}{2 \times 10^{8}}=1.5} \\

\mathrm{n_{B}=\frac{3 \times 10^{8}}{1.5 \times 10^{8}}=2}

\text{For TIR}

\mathrm{\theta>i_{c}}

\mathrm{\theta>\sin ^{-1}\left(\frac{1.5}{2}\right)}

\mathrm{\theta>\sin ^{-1}\left(\frac{3}{4}\right)}

Hence correct option is 4

Posted by

vishal kumar

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