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  • The standard entropy change for the reaction <img alt="4 \mathrm{Fc}(\mathrm{s})+3 \mathrm{O}_{2}\text{(g)}, 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~s}) \text { is }-550 \mathrm{~J} \ma

The standard entropy change for the reaction

4 \mathrm{Fc}(\mathrm{s})+3 \mathrm{O}_{2}\text{(g)}, 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~s}) \text { is }-550 \mathrm{~J} \mathrm{~K}^{-1} \text { at } 298 \mathrm{~K}
[Given : The standard enthalpy change for the reaction is -165 \mathrm{~kJ} \mathrm{~mol}^{-1} ]. The temperature in \mathrm{K} at which the reaction attains equilibrium is (Nearest Integer)

Option: 1

300


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

At equilibrium,

\\\Delta G=0\\ \\\Rightarrow \Delta H=T \Delta S\\ \\\Rightarrow T=\frac{\Delta H}{\Delta S}

\Rightarrow T=\frac{-165 \times 10^{3}}{-550}=300 \mathrm{~K}

Hence, the answer is 300

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mansi

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