Get Answers to all your Questions

header-bg qa

The stoichiometry and solubility product of a salt with the solubility curve given below, respectively:

 

Option: 1

X_{2}Y,2\times 10^{-9}M^{3}


Option: 2

XY_{2},1\times 10^{-9}M^{3}


Option: 3

XY_{2},4\times 10^{-9}M^{3}

 


Option: 4

XY,2\times 10^{-6}M^{3}


Answers (1)

1) \mathrm{X_2Y(s)\: \rightarrow \: 2X^{+}(aq)\: +\: Y^{-}(aq)}
                        
     2 X 10-3            10-3

Ksp = [X+ ]2 [Y ] =  (2 X10–3 )2 X 10–3  =  4 X 10–6

 

2) \mathrm{XY_2(s)\: \rightarrow \: X^{+}(aq)\: +\: 2Y^{-}(aq)}
                             
 10-3             2 X 10-3 

Ksp = [X+ ]2 [Y ] = 10–3  X  (2 X10–3 )2   =  4 X 10–6

 

3) \mathrm{XY(s)\: \rightarrow \: X^{+}(aq)\: +\: Y^{-}(aq)}
                              
 10-3              10-3

Ksp = [X+ ] [Y ] =  10–3 X 10–3  =  10–6

 

So, \mathrm{XY}_{2}, 4 \times 10^{-9} \mathrm{M}^{3} will be correct.

Therefore, Option(3) is correct.

Posted by

Sumit Saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions