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The straight line \mathrm{y=x-2} rotates about a point where it cuts the \mathrm{x}-axis and become perpendicular to the straight line \mathrm{a x+b y+c=0}. Then its equation

Option: 1

\mathrm{a x+b y+20=0}


Option: 2

\mathrm{a x-b y-2 a=0}


Option: 3

\mathrm{b x+a y-2 b=0}


Option: 4

\mathrm{a y-b x+2 b=0}


Answers (1)

best_answer

Slopes of the 4 line in the new position is b/a, since it is perpendicular to the line \mathrm{a x+b y+c= 0} and  it cuts the \mathrm{x}-axis.Hence the required line passes through (2,0) and its slope is \mathrm{b/a}.

The required is

\mathrm{y-0=\frac{b}{a}(x-2) \text { or } a y=b x-2 b}

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