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  • The straight lines <img alt="\mathrm{L_{1} \equiv 4 x-3 y+2=0, L_{2} \equiv 3 x+4 y-4=0\, and \, L_{3} \equiv x-7 y+6=0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BL_%7B1%7D%

The straight lines \mathrm{L_{1} \equiv 4 x-3 y+2=0, L_{2} \equiv 3 x+4 y-4=0\, and \, L_{3} \equiv x-7 y+6=0}

Option: 1

form a right angled triangle


Option: 2

 form a right angled isosceles triangle


Option: 3

are concurrent


Option: 4

none of these


Answers (1)

best_answer

Since the line \mathrm{L_{1}} and \mathrm{L_{2}} are perpendicular and angle between \mathrm{L_{1}} and \mathrm{L_{2}} is \mathrm{45^{\circ}} Hence the triangle will be right angled isosceles.

 

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