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The straight lines 4 a x+3 b y+c=0 where a+b+c=0 , will be concurrent, if point is

Option: 1

(4,3)


Option: 2

\left(\frac{1}{4}, \frac{1}{3}\right)


Option: 3

\left(\frac{1}{2}, \frac{1}{3}\right)


Option: 4

\mathrm{\text { None of these }}


Answers (1)

best_answer

The set of lines is 4 a x+3 b y+c=0 \text {, where } a+b+c=0

Eliminating c, we get 4 a x+3 b y-(a+b)=0 \Rightarrow a(4 x-1)+b(3 y-1)=0

They pass through the intersection of the lines 4 x-1=0  and 3 y-1=0 \quad \text { i.e., } \quad x=\frac{1}{4}, y=\frac{1}{3} \text { i.e., }\left(\frac{1}{4}, \frac{1}{3}\right)

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mansi

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