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  • The tangents to the hyperbola <img alt="\mathrm{x^2-y^2=3}

The tangents to the hyperbola \mathrm{x^2-y^2=3} are parallel to the straight line \mathrm{2 x+y+8=0}  at the following points

 

Option: 1

(2, 1) or (1, 2)


Option: 2

(2, −1) or (−2, 1)

 


Option: 3

(−1, −2)


Option: 4

(−2, −1)

 


Answers (1)

best_answer

Clearly tangents at (2, –1) or (–2, 1) are parallel to 2x + y + 8 = 0.

 

Posted by

Rishabh

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