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The tangents to the hyperbola $\mathrm{x^2-y^2=3}$ are parallel to the straight line $\mathrm{2 x+y+8=0}$ at the following points

Option: 1
(2, 1) or (1, 2)

Option: 2
(2, −1) or (−2, 1)

Option: 3
(−1, −2)

Option: 4
(−2, −1)

Answers (1)

best_answer

Clearly tangents at (2, –1) or (–2, 1) are parallel to 2x + y + 8 = 0.

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