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The time period of oscillation of a freely suspended magnet is 4 s. If it is broken in length into two equal parts and one part is suspended in the same way, its time period will be.

Option: 1

4 s


Option: 2

2 s


Option: 3

0.5 s


Option: 4

0.25 s


Answers (1)

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\mathrm{ T=2 \pi \sqrt{\frac{I}{M B_H},} ~~~~~~\begin{aligned} & M \rightarrow \frac{M}{2} \rightarrow \frac{1}{2} \text { th } \\ & I \rightarrow \frac{m L^2}{12} \rightarrow \frac{1}{8} \text { th } \end{aligned}}

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