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The transfer ratio \mathrm{\beta } of a transistor is 50. The input resistance of the transistor when used in common emitter configuration is \mathrm{1k\Omega }. The peak value of the collector ac current for an ac input voltage of 0.01 V peak is

Option: 1

100 \mu \mathrm{A}


Option: 2

250 \mu \mathrm{A}


Option: 3

500 \mu \mathrm{A}


Option: 4

800 \mu \mathrm{A}


Answers (1)

\mathrm{\begin{aligned} & \mathrm{I}_{\mathrm{b}}=\frac{\mathrm{V}_{\mathrm{i}}}{\mathrm{R}_{\mathrm{i}}}=\frac{0.01}{1 \times 10^3}=0.01 \times 10^{-3} \mathrm{amp} \\ & =0.01 \mathrm{~mA} \\ & \text { Further, } \mathrm{I}_{\mathrm{C}}=\beta \times \mathrm{I}_{\mathrm{b}}=50 \times 0.01 \\ & =0.5 \mathrm{~mA}=500 \mu \mathrm{A} \end{aligned}}

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Kshitij

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