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  • The transfer ratio of a transistor is 50. The input resistance of the transistor when used in common – emitter configuration is <img alt="\mathrm{1k\Omega }" src="https://entrancecorner.oncod

The transfer ratio of a transistor is 50. The input resistance of the transistor when used in common – emitter configuration is \mathrm{1k\Omega }. The peak value of the collector AC current for an AC input voltage of 0.01 V peak is

Option: 1

100\mu A


Option: 2

250\mu\: A


Option: 3

500 \: \mu\: A


Option: 4

800\: \mu\: A


Answers (1)

best_answer

Given that,

\mathrm{\begin{aligned} & V_1=0.01 \text { volt } \\ & R_l=1 \mathrm{k} \Omega=10^3 \Omega \\ & \therefore I_b=\frac{V_1}{R_1}=\frac{0.01}{1 \times 10^3}=0.01 \times 10^{-3} \Omega=0.01 \mathrm{~mA} \\ & \text { Further, } l_c=\beta l_b=50 \times 0.01 \mathrm{~mA} \\ & \quad=0.5 \mathrm{~mA}=500 \mu \mathrm{A} \end{aligned}}

Posted by

rishi.raj

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