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The value of \mathrm{\alpha } for a transistor is 0.9. What would be the change in the collector current corresponding to a change of 4 mA in the base current in a common emitter arrangement ?

Option: 1

36 mA


Option: 2

72 mA


Option: 3

18 mA


Option: 4

None of these


Answers (1)

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\mathrm{\Delta \mathrm{l}_{\mathrm{c}}=\beta \Delta \mathrm{l}_{\mathrm{b}}=\frac{\alpha \Delta \mathrm{l}_{\mathrm{b}}}{1-\alpha}=\frac{0.9 \times 4}{0.1}=36 \mathrm{~mA}}

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