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The value of  \sin(18^{\circ})+\sin (72^{\circ})-\sqrt{2}\cos(27^{\circ})\\ is

Option: 1

\frac{\sqrt{5}-1}{4}


Option: 2

\frac{-\sqrt{5}-1}{4}


Option: 3

\frac{\sqrt{5}+1}{4}


Option: 4

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Answers (1)

best_answer

\\\sin(18^{\circ})+\sin (72^{\circ})-\sqrt{2}\cos(27^{\circ})\\=2\sin(45^{\circ}) \cos 27^{\circ}-\sqrt{2}\cos(27^{\circ})\\ =0

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vishal kumar

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