Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The values of kinetic energy ‘K’ and potential energy ‘U’ are measured as follows :

$K = 100.0 \pm 2.0 J$

$U = 200.0 \pm 1.0 J$

Then the percentage error in the measurement of mechanical energy is :
Option: 1
2.5 %

Option: 2
1 %

Option: 3
0.5 %

Option: 4
1.5 %

Answers (1)

best_answer

$M_{E}=K+U=300.0\pm 3.0J=E\pm \Delta E.$

$\therefore \frac{\Delta E}{E}\times 100=1 \%$

Posted by

Rishabh

View full answer

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Latest Question