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The vapour pressures of two volatile liquids A and B at 25^{circ} mathrm{C} 	ext { are } 50 	ext { Torr and } 100 	ext { Torr. },  respectively. If the liquid mixture contains 0.3 mole fraction of A, then the mole fraction of liquid B in the vapour phase is frac{x}{17} . The value of x is ________.

Option: 1

14


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

From Raoult's Law

            \\\mathrm{ P_{A}=P_{A}^{0} X_{A}} \\\\ \mathrm{P_{B}=P_{B}^{0} X_{B} }

Thus, 

\mathrm{P_{A}= 50 \times 0.3=15 ~Torr}

\mathrm{P_{B}= 100 \times 0.7=70 ~Torr}

Now, mole fraction of B in vapor phase, \mathrm{{y_B}} is given as 

\mathrm{ y_B= \frac{P_B}{P_A+P_B}=\frac{70}{85}=\frac{14}{17}}

Answer is 14

Posted by

Suraj Bhandari

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