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  • The velocity of a particle executing SHM varies with displacement as <img alt="4 v^{2}=50-x^{2}" src="https://entrancecorner.

The velocity of a particle executing SHM varies with displacement x as 4 v^{2}=50-x^{2}. The time period of oscillations is \frac{x}{7} s. The value of x is _________.
\left(\right.$Take $\left.\pi=\frac{22}{7}\right)

Option: 1

88


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

4 v^{2}=50-x^{2}
V=\frac{1}{2} \sqrt{50-x^{2}}
\omega=\frac{1}{2}
T=\frac{2 \pi}{\omega}=4 \pi=\frac{88}{7}
x=88

Ans: (88)

Posted by

Pankaj

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