Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The velocity (v) and time (t) graph of the body in straight line motion is shown in the figure. The point S is at 4.33 seconds. The total distance covered by the body in 6 second is: <img alt="" src="https://cdn.entrance360.com/media/uploads/2020/09/21

The velocity (v) and time (t) graph of the body in straight line motion is shown in the figure. The point S is at 4.33 seconds. The total distance covered by the body in 6 second is:
Option: 1  (11/4)m
Option: 2 (49/4)m
Option: 3 (37/3)m
Option: 4 12m

Answers (1)

best_answer

Total distance=area under the v-t graph=area of trapezium(OABS)+area of triangle=\frac{1}{2}(4.333+1) \times 4+\frac{1}{2} \times 1.667 \times 2= \frac{37}{3} m

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA Counselling 2025 LIVE: BTech registration starts at josaa.nic.in for IIT, NIT, IIIT admissions
anam-khan

Kota: 17-year old student from UP preparing for JEE dies of electrocution in hostel
anam-khan

CSAB 2025 counselling dates out for special, supernumerary rounds through JEE Mains

Latest Question