Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The vertex of a right angle of a right angled triangle lies on the straight line $\mathrm{2 x+y-10=0}$ and the two other vertices, at points $(2,-3)$ and $(4,1)$ then the area of triangle in sq. units is
Option: 1
$\sqrt{10}$

Option: 2
$3$

Option: 3
$\frac{33}{5}$

Option: 4
$11$

Answers (1)

best_answer

$\mathrm{M}_{1} \mathrm{M}_{2}=-1$

$\frac{9-2 a}{a-4} \times \frac{13-2 a}{a-2}=-1$

$117-26 a-18 a+4$

$a^{2}=-\left(a^{2}-6 a+8\right)$

$5 a^{2}-50 a+125=0$

$a=5$

$\text{so} \: B\: is \: (5,0)$
$\text{so area }=\frac{1}{2} \mathrm{AB} \times \mathrm{AC}=\frac{1}{2} \sqrt{2} \times 3 \sqrt{2}=3$

Posted by

Shailly goel

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Trending Articles/News

anam-khan

JEE Mains 2026 April 8 LIVE: Day 6 exam for BTech from 3 pm today; guidelines, question paper analysis

anam-khan

JEE Main 2026 April 6 shift 2 exam ‘easy to moderate’; Maths toughest, Physics easier

anam-khan

JEE Main 2026 April 6 Shift 1: Students find Maths tough, chemistry slightly tough, physics calculation heavy

Latest Question