Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The vertices of the hyperbola <img alt="\mathrm{9 x^2-16 y^2-36 x+96 y-252=0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B9%20x%5E2-16%20y%5E2-36%20

The vertices of the hyperbola \mathrm{9 x^2-16 y^2-36 x+96 y-252=0} are 

 

Option: 1

 (6, 3) and (–6, 3)


Option: 2

(6, 3) and (–2, 3)


Option: 3

(–6, 3) and (–6, –3)


Option: 4

none of these


Answers (1)

best_answer

The equation of the hyperbola reduces to \mathrm{\frac{(x-2)^2}{16}-\frac{(y-3)^2}{9}=1}

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change
anam-khan

Faridabad: 17-year-old girl preparing for JEE Main 2026 dies by suicide
anam-khan

NTA JEE Mains 2026 application closes at 9 am today; correction facility from December 1

Latest Question