The vertices of the hyperbola are
(6, 3) and (–6, 3)
(6, 3) and (–2, 3)
(–6, 3) and (–6, –3)
none of these
The equation of the hyperbola reduces to
Study 40% syllabus and score up to 100% marks in JEE
50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
JEE Mains 2025 Paper 2 Answer Key LIVE: NTA final answer key PDF at jeemain.nta.nic.in soon; BArch result date
JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation
Four Kashmiri girls defy the odds, score 99+ percentile in JEE Main 2025
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now