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The wave function (\Psi) of 2 \mathrm{~s} is given by

\Psi_{2 \mathrm{~s}}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-r / 2 a_0}
At r=r_0, radial node is formed. Thus, r_0  in terms of a_0

Option: 1

r_0=4 a_0


Option: 2

r_0=\frac{a_0}{2}


Option: 3

r_0=a_0


Option: 4

r_0=2 a_0


Answers (1)

best_answer

At node  \psi_{2 \mathrm{~s}}=0

\begin{aligned} & 2-\frac{\mathrm{r}_0}{\mathrm{a}_0}=0 \\ & \mathrm{r}_0=2 \mathrm{a}_0 \end{aligned}

 

Posted by

Gautam harsolia

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