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The wave of wavelength 5900 \AA emitted by any atom or molecule must have some finite total length which is known as the coherence length. For sodium light, this length is 2.4 cm. The number of oscillations in this length will be

Option: 1

4.068 \times 10^8


Option: 2

4.068 \times 10^7


Option: 3

4.068 \times 10^6


Option: 4

4.068 \times 10^5


Answers (1)

best_answer

Number of oscillator in coherence length
\begin{aligned} & =\frac{l}{\lambda}=\frac{0.024}{5900 \times 10^{-10}} \\ & =4.068 \times 10^6 \end{aligned}

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manish painkra

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