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  • The wavelength of first member of Balmer Series is . Calculate the wavelength of second member of Lyman series.  <div class='q

The wavelength of first member of Balmer Series is 6563 \AA. Calculate the wavelength of second member of Lyman series.
 

Option: 1

1025.5 \AA


Option: 2

2050 \AA


Option: 3

6563 \AA


Option: 4

none of these


Answers (1)

best_answer

  \quad \quad \quad \quad \frac{1}{\lambda_1}=R\left(\frac{1}{2^2}-\frac{1}{3^2}\right)=\frac{5 R}{36}\\ \begin{aligned} & \frac{1}{\lambda_2}=R\left(\frac{1}{1^2}-\frac{1}{3^2}\right)=\frac{8 R}{9} \\ & \Rightarrow \frac{\lambda_2}{\lambda_1}=\frac{5}{32} \Rightarrow \lambda_2=\frac{5}{32} \lambda_1=1025.5 \AA \end{aligned}
 

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Gaurav

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