Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The work function of a certain metal is 3.31 \times 10^{-19} \mathrm{~J}. Then, the maximum kinetic energy of photoelectrons emitted by incident radiation of wavelength 5000 \AA  is
 

Option: 1

2.48 \mathrm{eV}


Option: 2

0.42 \mathrm{eV}


Option: 3

2.07 \mathrm{eV}


Option: 4

0.82 \mathrm{eV}


Answers (1)

best_answer

Here, work function, \phi_0=3.31 \times 10^{-19} \mathrm{~J}

Wavelength, \lambda=5000 \AA=5000 \times 10^{-10} \mathrm{~m}

Energy of the incident photon, \mathrm{E}=\frac{\mathrm{hc}}{\lambda}=\frac{6.63 \times 10^{-34} \times 3 \times 10^8}{5000 \times 10^{-10}}=3.98 \times 10^{-19} \mathrm{~J}

According to Einstein's photoelectric equation

\begin{aligned} & \mathrm{K}_{\max }=\mathrm{hv}-\phi_0=3.98 \times 10^{-19} \mathrm{~J}-3.31 \times 10^{-19} \mathrm{~J}=0.67 \times 10^{-19} \mathrm{~J} \\ & =\frac{0.67 \times 10^{-19}}{1.6 \times 10^{-19}} \mathrm{eV}=0.42 \mathrm{eV} \end{aligned}

Posted by

Nehul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering courses
anam-khan

JEE Main 2026: NIT Delhi cut-offs for BTech courses show ever-increasing demands for AI, computer skills
anam-khan

597 Eklavya school students clear JEE, NEET exams in 2024-25; Gujarat, MP lead

Latest Question