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The work function of a metal is 1.6\times 10^{-19}J When the metal surface is illuminated by the light of wavelength 6400 A , then the maximum kinetic energy of emitted photo-electron will be
(Planck's constant  h = 6.4 \times 10^{-34}Js )

Option: 1

15 \times10^{-19}J


Option: 2

2.8\times 10^{-19}J


Option: 3

1.5\times 10^{-19}J


Option: 4

1.5\times 10^{-19}eV


Answers (1)

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\begin{aligned} & 1.6 \times 10^{-19} \mathrm{~J}=1 \mathrm{eV} \\ & \mathrm{E}=\phi+\mathrm{k}_{\mathrm{m}} \\ & \frac{12420}{\lambda}=\phi+\mathrm{k}_{\mathrm{m}} \end{aligned}

k_m=1.5\times 10^{-19}J

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Shailly goel

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