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  • The young's modulus of brass and steel are respectively <img alt="10\times 10^{10} N/m^{2}" src="https://entrancecorner.oncodecogs.com/gif.latex?10%5Ctimes%2010%5E%7B10%7D%20N/m%5E%7B

The young's modulus of brass and steel are respectively 10\times 10^{10} N/m^{2}  and 2\times 10^{10} N/m^{2}. A brass and a steel wire of the same length are extended by 1 mm under the same force, the radii of the brass and steel wire are R_{B} and R_{S}  respectively. Then -

Option: 1

R_{S}=\sqrt{2}R_{B}


Option: 2

R_{S}=4R_{B}


Option: 3

R_{S}=\frac{R_{B}}{\sqrt{2}}


Option: 4

R_{S}=\frac{R_{B}}{4}


Answers (1)

best_answer

\Delta l=\frac{Fl}{AY}=\frac {Fl}{\pi R^{2}Y}

\Delta l, F\ and\ l\ are\ same.

Hence, R^{2}Y=Constant

\frac{R_S}{R_B}=\sqrt{\frac{Y_B}{Y_S}}=\sqrt{\frac{1}{2}}

R_S=\frac{R_B}{\sqrt2

 

Posted by

shivangi.bhatnagar

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