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There are four machines and it is known that exactly two of them are faulty. They are tested one by one in a random order till both the faulty machines are identified. Then the probability that only two tests will be required is

Option: 1

\frac{1}{3}


Option: 2

\frac{1}{6}


Option: 3

\frac{1}{2}


Option: 4

\frac{1}{4}


Answers (1)

best_answer

The required probability = (probability of the first being faulty) X (probability of the second being faulty when the first is faulty)

=\frac{2}{4} \times \frac{1}{3}=\frac{1}{6}

Posted by

Shailly goel

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