Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • There are two containers, with one containing 4 Red and 3 Green balls and the other containing 3 Blue and 4 Green balls. One ball is drawn at random from each container. The probability that one of

There are two containers, with one containing 4 Red and 3 Green balls and the other containing 3 Blue and 4 Green balls. One ball is drawn at random from each container. The probability that one of the balls is Red and the other is Blue will be

Option: 1

17


Option: 2

\frac{9}{49}


Option: 3

\frac{12}{49}


Option: 4

\frac{3}{7}


Answers (1)

best_answer

The required probability = (Prob. of drawing a red ball from '1') x (Prob. of drawing a blue ball from '2')

=\frac{4}{7} \cdot \frac{3}{7}=\frac{12}{49}

              \left ( {\because \text{Events are independent}} \right )

Posted by

Gaurav

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question