Thermal capacity (in J/K) of 18 g water is (s= 1cal/g-K)
As we have learned
Thermal Capacity -
-
Thermal capacity = ms = 18 * 1 cal / K
= 18 * 4.2 J / K = 75.6 J/k
50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now