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Three capacitors each of capacitance 1 \mu \mathrm{f}are connected in parallel. To this combination. a fourth capacitor of capacitance 1 \mu \mathrm{f} is connected in series. The resultant capacitance of the system is -

Option: 1

\mathrm{4\, \mu f}


Option: 2

\mathrm{2\, \mu f}


Option: 3

\mathrm{\frac{4}{3}\, \mu f}


Option: 4

\mathrm{\frac{3}{4}\, \mu f}


Answers (1)

best_answer



Use,
          \mathrm{C^{\prime}=c_{1}+c_{2}+c_{3}=3 \, \mu \mathrm{F}}
           \mathrm{\frac{1}{C_{A B}}=\frac{1}{c^{\prime}}+\frac{1}{c_{4}}=\frac{1}{3}+1=\frac{4}{3}}

\mathrm{ C_{A B}=3 / 4\, \mu \mathrm{f}} Ans

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chirag

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