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Three solenoid coils of same dimension, same number of turns and same number of layers of windings are taken. Coil 1 with inductance 1L was wound using a wire of resistance \mathrm{11\Omega/m } , coil 2 with inductance 2L was wound using the similar wire but the direction of winding was reversed in each layer, coil 3 with inductance 3L was wound using a superconducting wire. The self-inductance of the coils \mathrm {L_{1},L_{2}} ,  and \mathrm {L_{3}} are:

Option: 1

\mathrm{L}_1=\mathrm{L}_2=\mathrm{L}_3


Option: 2

\mathrm{L}_1=\mathrm{L}_2, \mathrm{~L}_3=0


Option: 3

\mathrm{L}_1=\mathrm{L}_3, \mathrm{~L}_2=0


Option: 4

\mathrm{L}_1>\mathrm{L}_2>\mathrm{L}_3


Answers (1)

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The self-inductance of a coil, \mathrm{\mathrm{L}=\mu_0 \mathrm{n}^2 \mathrm{~S} l} where \mathrm{\mu_0=} permeability of air,

n = number of turns per unit length,
S = area of cross-section and
l = length of the solenoid

This depends on the geometry of the inductor such as cross-sectional area, length and number of turns and not on the material, even if it is made of a superconducting material. If the superconductor is below the critical temperature, then the current will continuously flow and the inductance may not have the property of inductance any more.

\mathrm{\therefore \mathrm{L}_1=\mathrm{L}_2, \mathrm{~L}_3=0}

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Shailly goel

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